(3y-4)(2y^2+y-1)

Jasonbradley

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Jun 16, 2024

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Expanding the Expression (3y-4)(2y^2+y-1)

This article will guide you through the process of expanding the expression (3y-4)(2y^2+y-1).

Understanding the Process

Expanding this expression means multiplying each term in the first set of parentheses by each term in the second set of parentheses. This is a common technique in algebra and is often referred to as FOIL (First, Outer, Inner, Last).

Step-by-Step Expansion

1. First: Multiply the first term of each parenthesis: (3y)(2y^2) = 6y^3

2. Outer: Multiply the outer terms of each parenthesis: (3y)(-1) = -3y

3. Inner: Multiply the inner terms of each parenthesis: (-4)(2y^2) = -8y^2

4. Last: Multiply the last terms of each parenthesis: (-4)(y) = -4y

5. Combine: Add all the resulting terms together: 6y^3 - 3y - 8y^2 - 4y

6. Simplify: Combine like terms: 6y^3 - 8y^2 - 7y

Conclusion

Therefore, the expanded form of (3y-4)(2y^2+y-1) is 6y^3 - 8y^2 - 7y. Remember to always simplify your expressions by combining like terms for the most concise representation.